0=-6m^2+13m+28

Solution for 0=-6m^2+13m+28 equation:

0=-6m^2+13m+28

We move all terms to the left:

0-(-6m^2+13m+28)=0

We add all the numbers together, and all the variables

-(-6m^2+13m+28)=0

We get rid of parentheses

6m^2-13m-28=0

a = 6; b = -13; c = -28;
Δ = b2-4ac
Δ = -132-4·6·(-28)
Δ = 841
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{841}=29$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-13)-29}{2*6}=\frac{-16}{12}
=-1+1/3
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-13)+29}{2*6}=\frac{42}{12}
=3+1/2
$